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JEE CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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Analyzing +4 | -1
Consider the following statements
I. Chain and position isomerism are not possible together between two isomers
II. Tautomerism is a chemical phenomenon which is catalysed by acid as well as base
III. Tautomers are always metamers
IV. Tautomers are always functional isomers
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Correct option: D
I, II and IV are correct
The correct answer is D (I, II and IV are correct) because chain and position isomerism cannot occur together, tautomerism is acid/base catalyzed, and tautomers are functional isomers.

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Which has maximum paramagnetic character? Ionization of K[Ag(CN)2]\mathrm{K}\left[ {\mathrm{Ag}{{\left( {\mathrm{CN}} \right)}_2}} \right] will give: The cation that does not form an ammine complex with excess of ammonia is: The complexes [PtCl2(NH3)4]Br2  and  [PtBr2(NH3)4]Cl2  \left[ {\mathrm{PtC}{\mathrm{l}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{B}{\mathrm{r}_2}\mathrm{\;and\;}\left[ {\mathrm{PtB}{\mathrm{r}_2}{{\left( {\mathrm{N}{\mathrm{H}_3}} \right)}_4}} \right]\mathrm{C}{\mathrm{l}_2}\mathrm{\;} are example for isomerism The correct name of [Pt(NH3)4Cl2][PtCl4]\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_4 \mathrm{Cl}_2\right]\left[\mathrm{PtCl}_4\right] is: Which of the following pairs of isomers and types of isomerism are correctly matched?

(I) [Co(NH3)5(NO2)]Cl2\left[{Co}\left({NH}_3\right)_5\left({NO}_2\right)\right] {Cl}_2 and [Co(NH3)5(ONO)]Cl2………\left[{Co}\left({NH}_3\right)_5({ONO})\right] {Cl}_2 \ldots \ldots \ldots Linkage

(II) [Cu(NH3)4][PtCl4]  &  [Pt(NH3)4][CuCl4]………\left[{Cu}\left({NH}_3\right)_4\right]\left[{PtCl}_4\right] \,\, \& \,\, \left[{Pt}\left({NH}_3\right)_4\right]\left[{CuCl}_4\right] \ldots \ldots \ldots Coordinations

(III) [Pt(NH3)4Cl2]Br2  &  [Pt(NH3)4Br2]Cl2………\left[{Pt}\left({NH}_3\right)_4 {Cl}_2\right] {Br}_2 \, \, \& \, \, \left[{Pt}\left({NH}_3\right)_4 {Br}_2\right]{Cl}_2 \ldots \ldots \ldots Ionization

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