Question

$\smallint \frac{1}{{{{\left\{ {{{\left( {x - 1} \right)}^3}\,\,{{\left( {x + 2} \right)}^5}} \right\}}^{1/4}}}}dx$ is equal to

Accepted Answer

$\frac{4}{3}\,\,{\left( {\frac{{x\,\, - \,\,1}}{{x\,\, + \,\,2}}} \right)^{1/4}} + \,\,C$

Answer

$\frac{4}{3}\,\,{\left( {\frac{{x\,\, + \,\,2}}{{x\,\, - \,\,1}}} \right)^{1/4}} + \,\,C$

Answer

$\frac{1}{3}\,\,{\left( {\frac{{x\,\, - \,\,1}}{{x\,\, + \,\,2}}} \right)^{1/4}} + \,\,C$

Answer

$\frac{1}{3}\,\,{\left( {\frac{{x\,\, + \,\,2}}{{x\,\, - \,\,1}}} \right)^{1/4}} + \,\,C$

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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