NEET UG CHEMISTRY MCQ: 13 TH GROUP ELEMENTS (P-BLOCK)

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\mathrm{BX}_3+\mathrm{NH}_3 \stackrel{\text { R.T. }}{\longrightarrow} \mathrm{BX}_3 \cdot \mathrm{NH}_3+

Heat of adduct formation

(\Delta \mathrm{H}).

The numerical value of

\Delta \mathrm{H}

is found to be maximum for:

View answer and explanation

Correct option: D

\mathrm{BI}_3

The correct answer is D (BI3) because BI3 has the least pi-backbonding, leading to the strongest Lewis acid character and thus the maximum heat of adduct formation.

More Questions from 13 TH GROUP ELEMENTS (P-BLOCK)

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The hardest compound of boron is: Which does not show inert pair effect? Which one of the following does not exist in the free state On strong heating of

{H}_3 {PO}_4

and

{H}_3 {BO}_3

, sum of oxidation number of

{P}\, \& {~B}

in the final product obtained is Compound ‘X’ reacts with

N{H_3}

to 473 K give another compound ‘Y’. X can be prepared by heating

B{F_3}

with sodium hydride. The compound ‘Y’ is represented by the formula Assertion: Electronegativity first increases from B to Al and then decreases from Al to

\mathrm{TI}

.

Reason: Due to poor shielding by inner

\mathrm{d}

and

\mathrm{f}

electrons.