JEE MATHEMATICS MCQ: COMPLEX NUMBERS

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Analyzing +4 | -1

Given that

a,\;b \in \left\{ {0,\;1,\;2, \ldots ,9} \right\}

with

a + b \ne 0

and that

{\left( {a + \frac{b}{{10}}} \right)^x} = {\left( {\frac{a}{{10}} + \frac{b}{{100}}} \right)^y} = 1000

. Then,

\frac{1}{x} - \frac{1}{y}

is equal to

View answer and explanation

Correct option: C

\frac{1}{3}

Option C (

\frac{1}{3}

) is correct because by setting a = 0 and b = 1, we can solve for x and y and find that

\frac{1}{x} - \frac{1}{y} = \frac{1}{3}

More Questions from COMPLEX NUMBERS

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