JEE MATHEMATICS MCQ: MAXIMA & MINIMA

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\max \limits_{{0 \leq x \leq \pi}}\left\{x-2 \sin x \cos x+\frac{1}{3} \sin 3 x\right\}=

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Correct option: D

\frac{5 \pi+2+3 \sqrt{3}}{6}

Option D (

\frac{5 \pi+2+3 \sqrt{3}}{6}

) is correct because it represents the maximum value of the function within the given interval, found by analyzing the critical points.

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