Skip to main content
Back to ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

NEET UG CHEMISTRY MCQ: ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

1 Medium
1 of 1
Analyzing +4 | -1
The stability of

CH3−CH=CH−CH3,CH3(I)−C∣CH3=C∣CH3−CH3(II)CH3−C∣CH3=CH2(III)        CH3−C∣CH3=CH−CH3(IV)\begin{array}{l} \mathop {\mathrm{C}{\mathrm{H}_3} - \mathrm{CH} = \mathrm{CH} - \mathrm{C}{\mathrm{H}_3},\mathrm{C}{\mathrm{H}_3}}\limits_{(I)} - \mathop {\mathop {\mathop \mathrm{C}\limits_| }\limits_{C{H_3}} = \mathop {\mathop \mathrm{C}\limits_| }\limits_{C{H_3}} - \mathrm{C}{\mathrm{H}_3}}\limits_{(II)} \\ \mathop {\mathrm{C}{\mathrm{H}_3} - \mathop {\mathop \mathrm{C}\limits_| }\limits_{C{H_3}} = \mathrm{C}{\mathrm{H}_2}}\limits_{(III)} \mathrm{\;\;\;\;}\mathop {\mathrm{C}{\mathrm{H}_3} - \mathop {\mathop \mathrm{C}\limits_| }\limits_{C{H_3}} = \mathrm{CH} - \mathrm{C}{\mathrm{H}_3}}\limits_{(IV)} \end{array}

In the increasing order is

View answer and explanation
Correct option: A
III<I<IV<IIIII < I < IV < II
Option A (III<I<IV<IIIII < I < IV < II) is correct because the stability of alkenes increases with the number of alkyl substituents on the double-bonded carbons (more substituted alkenes are more stable).

More Questions from ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.