JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy

1 of 1

Application +4 | -1

If the function

y=\log \frac{1}{1+x}

satisfies the relation

x y^{\prime}

+1=f(y)

then

f(y)

is equal to

View answer and explanation

Correct option: C

e^y

Option D (

e^{-y}

) is correct because it satisfies the given relation after substituting the derivative of the function.

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y=y(x)

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x = A\cos 4t + B\sin 4t,

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y=y(t)

\frac{d y}{d t}+\alpha y=\gamma e^{-\beta t}

\alpha>0, \beta>0

\gamma>0

\lim \limits_{{x \rightarrow \infty}} y(t)