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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1
If b=2,c=3b=2, c=\sqrt{3} and ∠A=30∘\angle A=30^{\circ}, then inradius of △ABC\triangle A B C is
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Correct option: A
3−12\frac{\sqrt{3}-1}{2}
Option A (3−12\frac{\sqrt{3}-1}{2}) is correct because it is the correct inradius calculated using the given side lengths and angle.

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