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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1
A,B,C\mathrm{A}, \mathrm{B}, \mathrm{C} are the angles of a triangle, then sin⁡2A+sin⁡2 B+sin⁡2C−2cos⁡Acos⁡Bcos⁡C=\sin ^2 A+\sin ^2 \mathrm{~B}+\sin ^2 \mathrm{C}-2 \cos \mathrm{A} \cos \mathrm{B} \cos \mathrm{C}=
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Correct option: B
2
Option B (2) is correct because the trigonometric expression simplifies to 2 using trigonometric identities and the fact that A, B, and C are angles of a triangle.

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