JEE MATHEMATICS MCQ: STRAIGHT LINES

1 Easy

1 of 1

Analyzing +4 | -1

(i) The points

(-1,0),(4,-2)

and

(\cos 2 \theta, \sin 2 \theta)

are collinear

(ii) The points

(-1,0),(4,-2)

and

\left(\frac{1-\tan ^2 \theta}{1+\tan ^2 \theta}, \frac{2 \tan \theta}{1+\tan ^2 \theta}\right)

are collinear

View answer and explanation

Correct option: B

statemetn (i) has more solution than statement (ii) for

\theta

Option A (statement (i) has more solution than statement (ii) for

\theta

) is correct because statement (i) yields more solutions for

\theta

than statement (ii) due to the different trigonometric forms.

More Questions from STRAIGHT LINES

Practice All Chapter MCQs →

x-3 y=p, a x+2 y=q

a x+y=r

\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

(3,8)

x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0