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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1
If (sec⁡α+tan⁡α)(sec⁡β+tan⁡β)(sec⁡γ+tan⁡γ)(\sec \alpha+\tan \alpha)(\sec \beta+\tan \beta)(\sec \gamma+\tan \gamma) =tan⁡αtan⁡βtan⁡γ=\tan \alpha \tan \beta \tan \gamma, then expression (sec⁡α−tan⁡α)(sec⁡β−tan⁡β)(sec⁡γ−tan⁡γ)(\sec \alpha-\tan \alpha)(\sec \beta-\tan \beta)(\sec \gamma-\tan \gamma) is equal to
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Correct option: A
cot⁡αcot⁡βcot⁡γ\cot \alpha \cot \beta \cot \gamma
Option A (cot⁡αcot⁡βcot⁡γ\cot \alpha \cot \beta \cot \gamma) is correct because using the identity sec2x−tan2x=1sec^2 x - tan^2 x = 1 and the given equation, we can derive the expression.

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