JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Easy

1 of 1

Application +4 | -1

\int \frac{\sin ^{-1} x}{\left(1-x^2\right)^{1 / 2}} d x=

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Correct option: A

\frac{x}{\sqrt{1-x^2}} \sin ^{-1} x+\frac{1}{2} \log \left(1-x^2\right)+c

Option A (

\frac{{x}}{{\sqrt{{1-x^2}}}} \sin^{{-1}} x + \frac{{1}}{{2}} \log (1-x^2) + c

) is correct because the integral can be solved by substitution and then integration by parts.

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