JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

{\log _{\sqrt 3 }}\left( {\frac{{{{\left| z \right|}^2} - \left| z \right| + 1}}{{2 + \left| z \right|}}} \right)

< 2

, then the locus of

z

View answer and explanation

Correct option: B

\left| z \right| < 5

Option B (

\left| z \right| < 5

) is correct because solving the inequality results in the condition that the modulus of

z

must be less than 5.

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\left|\sum\limits_{r=1}^n z_r\right|

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\alpha, \beta

\gamma

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