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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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∫dx1−tan⁡2x=1λsin⁡−1(λsin⁡x)+C\int \frac{d x}{\sqrt{1-\tan ^2 x}}=\frac{1}{\lambda} \sin ^{-1}(\lambda \sin x)+C, then λ=\lambda=
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Correct option: A
2\sqrt{2}
Option A (2\sqrt{2}) is correct because by manipulating the integrand and using a trigonometric substitution, the integral can be solved, revealing that λ=2\lambda = \sqrt{2}.

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