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NEET UG PHYSICS MCQ: ALTERNATING CURRENT

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Application +4 | -1
AC voltage V(t) =20sin ωt= \mathrm{20 sin}\,\mathrm{\omega t} of frequency 50 Hz is applied to a parallel plate capacitor. The separation between the plates is 2 mm and the area is 1 m2.1\,{m^2}. The amplitude of the oscillating displacement current for the applied AC voltage is ….
[Take, ε0=8.85×10−12F/m]{\varepsilon _0} = 8.85 \times {10^{ - 12}}F/m]
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Correct option: C
27.79μA\mathrm{27}\mathrm{.79 \mu A}
Option C (27.79μA\mathrm{27}\mathrm{.79 \mu A}) is correct because the amplitude of the displacement current is calculated using the formula Id=ϵ0AdVdt1dI_d = \epsilon_0 A \frac{dV}{dt} \frac{1}{d}.

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