JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

1 Hard

1 of 1

Analyzing +4 | -1

Which reaction represents the oxidizing behaviour of

{H_2}S{O_4}

View answer and explanation

Correct option: D

2HI + {H_2}S{O_4} \to {I_2} + S{O_2} + 2{H_2}O

Option D (

2HI + {H_2}S{O_4} \to {I_2} + S{O_2} + 2{H_2}O

) represents the oxidizing behavior of

{H_2}S{O_4}

because sulfur is reduced from +6 to +4, while iodide is oxidized to iodine.

More Questions from P-BLOCK ELEMENTS

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17^{\text {th }}

{O}_2

{O}_2

\mathrm{C}{\mathrm{N}^ - }

{\mathrm{N}_2}

\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2}

2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+}

{H}_2 {~S}_2 {O}_8

{S}={O}

{S}-{OH}

{O}-

{O}

{NH}_3

{H}_2 {SO}_4

{H}_2 {SO}_4