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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Let CC be right angle of a △ABC\triangle A B C, then sin⁡2Asin⁡2B−cos⁡2Acos⁡2B\frac{\sin ^2 A}{\sin ^2 B}-\frac{\cos ^2 A}{\cos ^2 B} is equal to
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Correct option: B
a4−b4a2b2\frac{a^4-b^4}{a^2 b^2}
Option B (a4−b4a2b2\frac{{a^4-b^4}}{{a^2 b^2}}) is correct because it results from substituting the sine and cosine ratios in terms of sides a and b and simplifying the expression.

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