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JEE CHEMISTRY MCQ: AMINES

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Analyzing +4 | -1
Benzyl amine cannot be prepared by
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Correct option: D
C6H5CH2NC→  LiAlH4  {\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{NC}\mathop \to \limits^{\mathrm{\;LiAl}{\mathrm{H}_4}\mathrm{\;}}
Option D is correct because C6H5CH2NC{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_2}\mathrm{NC} on reduction with LiAlH4{\mathrm{LiAl}{\mathrm{H}_4}} gives a secondary amine, not benzyl amine.

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Identify 'Z\mathrm{Z}' in the sequence

C6H5NH2→NaNO2+HClX→CuCNY→H+/H2OZ{{\text{C}}_6}{{\text{H}}_5}{\text{N}}{{\text{H}}_2}\xrightarrow{{{\text{NaN}}{{\text{O}}_2} + {\text{HCl}}}}{\text{X}}\xrightarrow{{{\text{CuCN}}}}{\text{Y}}\xrightarrow{{{{\text{H}}^ + }/{{\text{H}}_2}{\text{O}}}}{\text{Z}} The primary, secondary and tertiary amines can be distinguished by: Assertion: The main product of reaction of alcoholic silver nitrite and ethyl bromide is nitroethane.

Reason: Silver nitrite is predominantly covalent compound. Hofmann’s bromamide reaction is to convert Gabriel phthalamide synthesis is used for preparation of :- Elements found in explosive are:
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