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JEE MATHEMATICS MCQ: FUNCTIONS

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Analyzing +4 | -1
If f(x)=22x22x+2,x∈R,f(x)=\frac{2^{2 x}}{2^{2 x}+2}, x \in \mathbb{R}, then f(12023)+f(22023)+…+f(20222023)f\left(\frac{1}{2023}\right)+f\left(\frac{2}{2023}\right)+\ldots+f\left(\frac{2022}{2023}\right) is equal to
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Correct option: C
1011
Option C (1011) is correct because the sum can be simplified by pairing terms f(x) and f(1-x), where f(x) + f(1-x) = 1.

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