JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

f: R \rightarrow R, g: R \rightarrow R

be two given functions, then

f(x)=2 \min (f(x)-g(x), 0)

equals

View answer and explanation

Correct option: D

f(x)-g(x)-|g(x)-f(x)|

Option D (

f(x)-g(x)-|g(x)-f(x)|

) is correct because it correctly represents 2min(f(x)-g(x), 0) using the absolute value function.

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S=\left\{x: f(x)=f^{-1}(x)\right\}