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NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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The magnetic moment of K3[Fe(CN)6]{\mathrm{K}_3}\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_6}} \right] is found to be 1.7 BM. How many unpaired electron (s) is/are present per molecule?
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Correct option: A
1
Option A (1) is correct because the magnetic moment of 1.7 BM indicates the presence of one unpaired electron in the complex.

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