JEE PHYSICS MCQ: OSCILLATIONS

Statement-I: In simple harmonic motion $A$ is the amplitude of oscillation. If $t_1$ be the time to reach the particle from mean position to $\frac{A}{\sqrt{2}}$ and $t_2$ the time to reach from $\frac{A}{\sqrt{2}}$ to $A$. Then $t_1=\frac{t_2}{\sqrt{2}}$

Statement-II: Equation of motion for the particle starting from mean position is given by $x= \pm \mathrm{A} \sin \omega \mathrm{t}$ and of the particle starting from extreme position is given by $x= \pm$ $A\cos \omega t$