The oxoacid of ${\rm{S}}{{\rm{O}}_2}$ is:

${{\rm{H}}_2}{\rm{S}}{{\rm{O}}_3}$

${{\rm{H}}_2}{\rm{S}}{{\rm{O}}_4}$

${{\rm{H}}_2}{{\rm{S}}_2}{{\rm{O}}_8}$

JEE CHEMISTRY MCQ: P-BLOCK ELEMENTS

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The oxoacid of

\mathrm{S}{\mathrm{O}_2}

is:

View answer and explanation

Correct option: A

{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_3}

Option A (

{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_3}

) is correct because it is the oxoacid formed when sulfur dioxide (

\mathrm{S}{\mathrm{O}_2}

) reacts with water.

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17^{\text {th }}

{O}_2

{O}_2

\mathrm{C}{\mathrm{N}^ - }

{\mathrm{N}_2}

\mathrm{C}{\mathrm{N}^ - },\mathrm{\;}{\mathrm{N}_2}

2 {Fe}^{3+}+{SO}_2+2 {H}_2 {O} \rightarrow 2 {Fe}^{2+}+{SO}_4^{2-}+4 {H}^{+}

{H}_2 {~S}_2 {O}_8

{S}={O}

{S}-{OH}

{O}-

{O}

{NH}_3

{H}_2 {SO}_4

{H}_2 {SO}_4