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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Understanding +4 | -1
Consider the following statements for the reaction between zinc and oxygen.

2Zn(s)+O2(g)⟶2ZnO(s);ΔH=−693.8 kJ mol−1\begin{aligned} & 2 \mathrm{Zn(s})+\mathrm{O}_2(\mathrm{g}) \longrightarrow 2 \mathrm{ZnO(s}) ; \\ & \Delta H=-693.8 \mathrm{~kJ~mol}^{-1} \end{aligned}

I. The enthalpy of two moles of ZnO\mathrm{ZnO} is less than the total enthalpy of two moles of Zn\mathrm{Zn} and one mole of oxygen by 693.8 kJ693.8 \mathrm{~kJ}

II. The enthalpy of two moles of ZnO\mathrm{ZnO} is more than the total enthalpy of two moles of Zn\mathrm{Zn} and one mole of oxygen by 693.8 kJ693.8 \mathrm{~kJ}

III. 693.8 kJ mol−1693.8 \mathrm{~kJ} \mathrm{~mol}^{-1} energy is evolved in the reaction

IV. 693.8 kJ mol−1693.8 \mathrm{~kJ} \mathrm{~mol}^{-1} energy is absorbed in the reaction

Select the correct statements and choose the correct option.
View answer and explanation
Correct option: B
I and III
Option B is correct. Statement I is correct because the reaction is exothermic, so the products have lower enthalpy. Statement III is also correct because the negative ΔH\Delta H indicates energy is evolved.

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