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JEE PHYSICS MCQ: OSCILLATIONS

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A particle executing simple harmonic motion has an amplitude of

6 \mathrm{~cm}

. Its acceleration at a distance of

2 \mathrm{~cm}

from the mean position is

8 \mathrm{cms}^{-2}

. The maximum speed of the particle is

View answer and explanation

Correct option: B

12 \mathrm{~cms}^{-1}

Option B (

12 \mathrm{~cms}^{-1}

) is correct because it represents the maximum speed of the particle, calculated using the given acceleration and amplitude.

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a

. When the PE of a particle is one-fourth of its maximum value during the oscillation, its displacement from the equilibrium position will be The displacement, velocity and acceleration in a simple harmonic motion are related as the Assertion: Angular velocity of earth around sun is lesser than the angular velocity of moon about earth.
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SHM

. At a displacement

{y_1}

its potential energy is

{U_1}

and at a displacement

{y_2}

its potential energy is

{U_2}

. The potential energy of the particle at displacement

\left( {{y_1} + {y_2}} \right)