JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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Application +4 | -1

In a triangle

\mathrm{ABC}

\cot ^{\frac{\mathrm{A}}{2}} \cot ^{\frac{\mathrm{B}}{2}}=\mathrm{c}

\cot ^{\frac{\mathrm{B}}{2}} \cot ^{\frac{\mathrm{C}}{2}}=\mathrm{a}

and

\cot \frac{C}{2} \cot ^{\frac{A}{2}}=b

, then

\frac{1}{s-a}+\frac{1}{s-b}+\frac{1}{s-c}=

View answer and explanation

Correct option: D

Option D (2) is correct because the given cotangent relationships lead to the simplification of the expression to 2.

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