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JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

If

f(x)=e^{2 x}

and

g(x)=\log \sqrt{x}(x > 0)

, then

f \circ g(x)

is equal to

View answer and explanation

Correct option: D

x

Option D (

x

) is correct because

f(g(x)) = e^{2 \log \sqrt{x}} = e^{\log x} = x

.

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