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JEE MATHEMATICS MCQ: FUNCTIONS

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Application +4 | -1
If fβ€…β€Š:Nβ†’Nf\;:N \to N is defined by f(n)=f\left( n \right) = the sum of positive divisors of nn, then f(2kΓ—3),f\left( {{2^k} \times 3} \right), where kk is a positive integer, is
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Correct option: C
3(2k+1βˆ’1)3\left( {{2^{k + 1}} - 1} \right)
Option C (3(2k+1βˆ’1)3\left( {{2^{k + 1}} - 1} \right)) is correct because it represents the sum of the positive divisors of 2kΓ—32^k \times 3.

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