For the reaction, $\begin{array}{l} {{\rm{H}}_2}\left( {\rm{g}} \right) + {\rm{C}}{{\rm{l}}_2}\left( {\rm{g}} \right) \to 2{\rm{HCl}}\left( {\rm{g}} \right) + {x_1}\,\,{\rm{kJ}} \ldots \ldots \ldots \left( {\rm{i}} \right)\\ 2{\rm{HCl}}\left( {\rm{g}} \right) \to {{\rm{H}}_2}\left( {\rm{g}} \right) + {\rm{C}}{{\rm{l}}_2}\left( {\rm{g}} \right) - {x_2}\,{\rm{kJ}} \ldots \ldots \left( {{\rm{ii}}} \right) \end{array}$ Which of the following statement is correct?

${x_1}$ and ${x_2}$ are numerically different

NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Understanding +4 | -1

For the reaction,

\begin{array}{l} {\mathrm{H}_2}\left( \mathrm{g} \right) + \mathrm{C}{\mathrm{l}_2}\left( \mathrm{g} \right) \to 2\mathrm{HCl}\left( \mathrm{g} \right) + {x_1}\,\,\mathrm{kJ} \ldots \ldots \ldots \left( \mathrm{i} \right)\\ 2\mathrm{HCl}\left( \mathrm{g} \right) \to {\mathrm{H}_2}\left( \mathrm{g} \right) + \mathrm{C}{\mathrm{l}_2}\left( \mathrm{g} \right) - {x_2}\,\mathrm{kJ} \ldots \ldots \left( {\mathrm{ii}} \right) \end{array}

Which of the following statement is correct?

View answer and explanation

Correct option: A

{x_1}

  and 

{x_2}

  are numerically equal

Option A (

{x_1}

  and 

{x_2}

  are numerically equal) is correct because the forward and reverse reactions have the same magnitude of enthalpy change, but opposite signs.