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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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If in △ABC,2b2=a2+c2\triangle A B C, 2 b^2=a^2+c^2, then sin⁡3Bsin⁡B=\frac{\sin 3 B}{\sin B}=
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Correct option: D
(c2−a22ca)2\left(\frac{c^2-a^2}{2 c a}\right)^2
Option D ((c2−a22ca)2\left(\frac{c^2-a^2}{2 c a}\right)^2) is correct because it is the simplified form of the expression sin⁡3Bsin⁡B\frac{\sin 3B}{\sin B} using the given condition and trigonometric identities.

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