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JEE PHYSICS MCQ: OSCILLATIONS

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The equation of a simple harmonic motion is given by

y=6 \sin 10 \pi t+8 \cos 10 \pi t

, where

y

is in cm and

t

in sec. Determine the period and initial phase.

View answer and explanation

Correct option: A

0.2 \mathrm{~s}, 53^{\circ} 8^{\prime}

Option A (

0.2 \mathrm{~s}, 53^{\circ} 8^{\prime}

) is correct because it correctly calculates the period and initial phase by comparing the given equation with the standard SHM equation.

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{y_1}

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{y_2}

its potential energy is

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\left( {{y_1} + {y_2}} \right)