JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

1 Easy

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Application +4 | -1

The solution of

y^{\prime \prime}-4 y^{\prime}+3 y=0, y(0)=6

and

y^{\prime}(0)=10

View answer and explanation

Correct option: A

y=4 e^x+2 e^{3 x}

Option A (

y=4 e^x+2 e^{3 x}

) is correct because it satisfies the given differential equation and the initial conditions y(0)=6 and y'(0)=10.

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y=y(t)

\frac{d y}{d t}+\alpha y=\gamma e^{-\beta t}

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\lim \limits_{{x \rightarrow \infty}} y(t)