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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy
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Application +4 | -1
If f(x)=cos⁡2  x+sec⁡2  xf\left( x \right) = {\cos ^2}\,\,x + {\sec ^2}\,\,x, its value always is
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Correct option: B
f(x)=1f\left( x \right) = 1
Option D (f(x)≥2f(x) \ge 2) is correct because the minimum value of cos⁡2x+sec⁡2x{\cos ^2}x + {\sec ^2}x occurs when cos⁡2x=1\cos^2 x = 1 and sec⁡2x=1\sec^2 x = 1, so the minimum value is 2.

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