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NEET UG PHYSICS MCQ: ATOMS

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Analyzing +4 | -1
Consider a hydrogen like atom whose energy in nth \mathrm{n}^{\text {th }} excited state is given by

En=−13.6n2Z2E_n=-\frac{13.6}{n^2} Z^2
when this excited atom makes a transition from an excited state to ground state. The most energetic photons have energy Emax⁡=52.224eV\mathrm{E}_{\max }=52.224 \mathrm{eV} and the least energetic photons have energy Emin⁡=1.224eV\mathrm{E}_{\min }=1.224 \mathrm{eV}. Find the atomic number of atom.
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Correct option: A
2
Option A (2) is correct because the atomic number can be determined from the given energy values using the formula for energy levels in a hydrogen-like atom.

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