If $A=130^{\circ}$ and $x=\sin A+\cos A$, then

JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy

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Application +4 | -1

A=130^{\circ}

and

x=\sin A+\cos A

, then

View answer and explanation

Correct option: A

x > 0

The correct answer is A (

x > 0

) because when

A = 130^{\circ}

x = \sin A + \cos A = \sin 130^{\circ} + \cos 130^{\circ} = \sin 50^{\circ} - \cos 50^{\circ}

, and since

\sin 50^{\circ} > |\cos 50^{\circ}|

x

is positive.

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\triangle A B C

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\sin ^2(A / 2)+\sin ^2(B / 2)-\sin ^2(C / 2)=