JEE MATHEMATICS MCQ: MAXIMA & MINIMA

1 Hard

1 of 1

Analyzing +4 | -1

The minimum & maximum value of

f(x)=\sin (\cos x)+\cos (\sin x)

for

-\frac{\pi}{2} \leq x \leq \frac{\pi}{2}

are respectively

View answer and explanation

Correct option: A

\cos 1

and

1+\sin 1

Option A,

\cos 1

and

1+\sin 1

, is correct because the maximum of the function occurs at x=0 and the minimum occurs at x=

\pi/2

due to the decreasing nature of the function in the given interval.

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