JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

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Application +4 | -1

A B C

is an equilateral triangle such that

\sqrt{\sin A}+\sqrt{\sin B}+\sqrt{\sin C}=\sqrt{k \cos \frac{A}{2} \cos \frac{B}{2} \cos \frac{C}{2}}

. Then find the value of '

k

View answer and explanation

Correct option: A

Option A (12) is correct because substituting A=B=C=60 degrees into the given equation and simplifying leads to k=12.

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