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JEE MATHEMATICS MCQ: TRIGONOMETRY RATIOS

1 Easy
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Application +4 | -1
If tan⁡θ=1/3\tan \theta=1 / \sqrt{3}, then the value of 3cos⁡2θ+sin⁡2θ\sqrt{3} \cos 2 \theta+\sin 2 \theta is
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Correct option: A
3\sqrt{3}
Option A (3\sqrt{3}) is correct because substituting tan⁡θ=1/3\tan \theta = 1/\sqrt{3} into the expression 3cos⁡2θ+sin⁡2θ\sqrt{3} \cos 2 \theta+\sin 2 \theta yields 3\sqrt{3}.

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