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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

1 Easy
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Application +4 | -1
In previous problem if expansion is carried out freely (Pext=0)\left(P_{\mathrm{ext}}=0\right), then ΔS\Delta S is :
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Correct option: C
Rln⁡3R \ln 3
Option C (Rln⁡3R \ln 3) is correct because for free expansion, the change in entropy is given by ΔS=nRln⁡(V2V1)\Delta S = nR \ln(\frac{V_2}{V_1}). Since the volume increases by a factor of 3 (from the previous problem), ΔS=Rln⁡3\Delta S = R \ln 3.

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