Skip to main content
Back to INDEFINITE INTEGRATION

JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

1 Medium
1 of 1
Analyzing +4 | -1
∫x  { f (x2)g′′  (x2)  −  f′′(x2)  g  (x2)}dx\int x\,\,\left\{ {\,f\,\left( {{x^2}} \right)\mathrm{g''}\,\,\left( {{x^2}} \right)\,\, - \,\,f''\left( {{x^2}} \right)\,\,\mathrm{g}\,\,\left( {{x^2}} \right)} \right\}dx is equal to
View answer and explanation
Correct option: C
12  { f(x2)  g′  (x2)  −  g  (x2)  f′  (x2)}  +  c\frac{1}{2}\,\,\left\{ {\,f\left( {{x^2}} \right)\,\,\mathrm{g'}\,\,\left( {{x^2}} \right)\,\, - \,\,\mathrm{g}\,\,\left( {{x^2}} \right)\,\,f'\,\,\left( {{x^2}} \right)} \right\}\,\, + \,\,c
Option C (\frac{1}{2}\left{ f\left( {{x^2}} \right)\g'\left( {{x^2}} \right) - g\left( {{x^2}} \right)\f'\left( {{x^2}} \right)} \right} + c\frac{1}{2}\left{ f\left( {{x^2}} \right)\g'\left( {{x^2}} \right) - g\left( {{x^2}} \right)\f'\left( {{x^2}} \right)} \right} + c) is correct because it is the result of applying integration by parts and substitution to the given integral.

More Questions from INDEFINITE INTEGRATION

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.