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JEE MATHEMATICS MCQ: INDEFINITE INTEGRATION

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Application +4 | -1
I=∫11−e2xdxI=\int \frac{1}{\sqrt{1-e^{2 x}}} d x is equal to
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Correct option: C
ln⁡∣tan⁡(sin⁡−1ex2)∣+c\operatorname{ln} \left|\tan \left(\frac{\sin ^{-1} e^x}{2}\right)\right|+c
Option C is correct because the integral simplifies to ln⁡∣tan⁡(sin⁡−1ex2)∣+c\ln \left|\tan \left(\frac{\sin ^{-1} e^x}{2}\right)\right|+c after substitution and simplification using trigonometric identities.

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