If $|z|=1$ and $w=\frac{z-1}{z+1},(z \neq-1)$, then $\operatorname{Re}(w)=$

$\left|\frac{1}{z+1}\right| \frac{1}{|z+1|^2}$

JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

|z|=1

and

w=\frac{z-1}{z+1},(z \neq-1)

, then

\operatorname{Re}(w)=

View answer and explanation

Correct option: A

Option A (0) is correct because by substituting

w=u+iv

and using

|z|=1

, we find that the real part of w, Re(w), is 0.

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