Ammoniacal solution of ${\rm{Ni}}{\left( {{\rm{CN}}} \right)_2}$ reacts with ${{\rm{C}}_6}{{\rm{H}}_6}$ to produce a light violet coloured crystalline compound of the formula:

${\rm{Ni}}{\left( {{\rm{CN}}} \right)_2}{\rm{N}}{{\rm{H}}_3} \cdot {{\rm{C}}_6}{{\rm{H}}_6}$

${\rm{Ni}}{\left( {{\rm{CN}}} \right)_2} \cdot {{\rm{C}}_6}{{\rm{H}}_5}$

${{\rm{C}}_6}{{\rm{H}}_5}{\rm{C}}{{\rm{H}}_3}$

${\rm{Ni}}{\left( {{\rm{CN}}} \right)_2}{{\rm{C}}_6}{{\rm{H}}_6}$

NEET UG CHEMISTRY MCQ: CO-ORDINATION COMPOUNDS

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Understanding +4 | -1

Ammoniacal solution of

\mathrm{Ni}{\left( {\mathrm{CN}} \right)_2}

reacts with

{\mathrm{C}_6}{\mathrm{H}_6}

to produce a light violet coloured crystalline compound of the formula:

View answer and explanation

Correct option: D

\mathrm{Ni}{\left( {\mathrm{CN}} \right)_2}\mathrm{N}{\mathrm{H}_3} \cdot {\mathrm{C}_6}{\mathrm{H}_6}

Option D (

\mathrm{Ni}{\left( {\mathrm{CN}} \right)_2}\mathrm{N}{\mathrm{H}_3} \cdot {\mathrm{C}_6}{\mathrm{H}_6}

) is correct because the reaction involves the formation of a complex containing nickel cyanide, ammonia, and benzene.