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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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Application +4 | -1

If momentum will increase by

0.3 \%

and mass will decrease by

0.2 \%

, then find out percentage change in kinetic energy.

View answer and explanation

Correct option: A

0.8 \%

Option A (0.8 %) is correct because the percentage change in kinetic energy is calculated using the formula

\frac{\Delta K}{K} \times 100 = \frac{2 \Delta p}{p} \times 100 - \frac{\Delta m}{m} \times 100

.

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