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JEE PHYSICS MCQ: OSCILLATIONS

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Two particles are executing SHMs. The equations of their motions are

y_1=10 \sin \left(\omega t+\frac{\pi}{4}\right) \text { and } y_2=5 \sin \left(\omega t+\frac{\sqrt{3} \pi}{4}\right)

What is the ratio of their amplitudes?

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Correct option: B

2: 1

Option B is correct because the ratio of the amplitudes is simply the ratio of the coefficients of the sine functions, which is 10/5 = 2/1.

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