JEE MATHEMATICS MCQ: FUNCTIONS

1 Easy

1 of 1

Application +4 | -1

The domain of definition of

f\left( x \right) = {\sin ^{ - 1}}\left( {\left| {x - 1} \right| - 2} \right)

View answer and explanation

Correct option: A

\left[ { - 2,\;0} \right] \cup \left[ {2,\;4} \right]

Option A ([{- 2,\;0}] ∪ [{2,\;4}]) is correct because it represents the values of x for which the argument of the inverse sine function lies between -1 and 1.

More Questions from FUNCTIONS

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f:(-\infty, 2] \longrightarrow(-\infty, 4]

, where

f(x)=x(4-x)

, then

f^{-1}(x)

is given by: If

g(f(x))=|\sin x|

and

f(g(x))=(\sin \sqrt{x})^2

, then Let

f:\left( {2,\;3} \right) \to \left( {0,\;1} \right)

be defined by

f\left( x \right) = x - \left[ x \right]

, then

{f^{ - 1}}\left( x \right)

equals Let

f: R \rightarrow R

be defined as

f(x)=x^4

, Choose the correct answer. Which of the following functions are odd functions Let

f(x)=(x+1)^2-1(x \geq-1)

. Then the set

S=\left\{x: f(x)=f^{-1}(x)\right\}

contains