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JEE PHYSICS MCQ: KINETIC THEORY OF GASES

1 Medium
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Application +4 | -1
Let AA and BB the two gases and given TBMA=4.TBMB;\frac{{{T_B}}}{{{M_A}}} = 4.\frac{{{T_B}}}{{{M_B}}}; where TT is the temperature and MM is molecular mass. If CA{C_A} and CB{C_B} are the r.m.s.r.m.s. speed, then the ratio CACB\frac{{{C_A}}}{{{C_B}}} will be equal to
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Correct option: A
2
Option A (2) is correct because the ratio of RMS speeds is proportional to the square root of the ratio of (T/M).

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