JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

1 Easy

1 of 1

Application +4 | -1

\triangle A B C

, if

c^2+a^2=2 b^2

, then value of

\frac{\cot B}{\cot C+\cot A}=

View answer and explanation

Correct option: B

\frac{1}{2}

Option B (

\frac{1}{2}

) is correct because it simplifies to

\frac{1}{2}

after applying trigonometric identities and the given condition

c^2 + a^2 = 2b^2

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