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JEE PHYSICS MCQ: GRAVITATION

1 Hard

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Application +4 | -1

An astronaut takes a ball of mass

m

from earth to space. He throws the ball into a circular orbit about earth at an altitude of

318.5 \mathrm{~km}

. From earth's surface to the orbit, the change in total mechanical energy of the ball is

x \frac{G M_e m}{21 R_e}

. The value of

x

is (take

\left.{R}_{{e}}=6370 \mathrm{~km}\right)

:

View answer and explanation

Correct option: A

11

Option A (11) is correct because it is the calculated value of x based on the change in total mechanical energy from Earth's surface to the orbit.

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. If the body is projected in a direction making an angle of

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v_e

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