The domain of $ \mathrm{F}(x)=\frac{\log _{2}(x+3)}{x^{2}+3 x+2} $ is

JEE MATHEMATICS MCQ: FUNCTIONS

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The domain of

\mathrm{F}(x)=\frac{\log _{2}(x+3)}{x^{2}+3 x+2}

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Correct option: D

(-3, \infty)-\{-1,-2\}

Option D is correct because the domain requires x+3 > 0 and the denominator not equal to zero, leading to the interval (-3, infinity) excluding -1 and -2.

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